(x-5)/(x^2-3x-10)

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Solution for (x-5)/(x^2-3x-10) equation: 


D( x )

x^2-(3*x)-10 = 0

x^2-(3*x)-10 = 0

x^2-(3*x)-10 = 0

x^2-3*x-10 = 0

x^2-3*x-10 = 0

DELTA = (-3)^2-(-10*1*4)

DELTA = 49

DELTA > 0

x = (49^(1/2)+3)/(1*2) or x = (3-49^(1/2))/(1*2)

x = 5 or x = -2

x in (-oo:-2) U (-2:5) U (5:+oo)

(x-5)/(x^2-(3*x)-10) = 0

(x-5)/(x^2-3*x-10) = 0

x^2-3*x-10 = 0

x^2-3*x-10 = 0

DELTA = (-3)^2-(-10*1*4)

DELTA = 49

DELTA > 0

x = (49^(1/2)+3)/(1*2) or x = (3-49^(1/2))/(1*2)

x = 5 or x = -2

(x+2)*(x-5) = 0

(x-5)/((x+2)*(x-5)) = 0

x-5 = 0 // + 5

x = 5

x in { 5} 

x belongs to the empty set

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